JEE Advanced 2024 · Paper 1 · numerical answer

JEE Advanced 2024 Chemistry question on Chemical Kinetics

Consider the following reaction, 2H2(g)+2NO(g)→N2(g)+2H2O(g)2\mathrm{H_2(g)} + 2\mathrm{NO(g)} \rightarrow \mathrm{N_2(g)} + 2\mathrm{H_2O(g)} which follows the mechanism given below: 2NO(g)⇌k1k−1N2O2(g)2\mathrm{NO(g)} \underset{k_{-1}}{\overset{k_1}{\rightleftharpoons}} \mathrm{N_2O_2(g)} (fast equilibrium); N2O2(g)+H2(g)→k2N2O(g)+H2O(g)\mathrm{N_2O_2(g)} + \mathrm{H_2(g)} \overset{k_2}{\rightarrow} \mathrm{N_2O(g)} + \mathrm{H_2O(g)} (slow reaction); N2O(g)+H2(g)→k3N2(g)+H2O(g)\mathrm{N_2O(g)} + \mathrm{H_2(g)} \overset{k_3}{\rightarrow} \mathrm{N_2(g)} + \mathrm{H_2O(g)} (fast reaction). The order of the reaction is ______.
Show answer

Answer: 3

[JEE Advanced 2024 · Paper 1]

Practise Chemical Kinetics the way it is asked

A timed set of real JEE Advanced Chemical Kinetics questions, graded as the exam grades. No sign-up.

Start a Chemical Kinetics test

More: all JEE Advanced Chemical Kinetics questions · JEE Advanced 2024 · Chemistry chapter list