JEE Advanced 2024 · Paper 1

JEE Advanced 2024 Mathematics question on Conic Sections

Consider the ellipse x29+y24=1\dfrac{x^{2}}{9}+\dfrac{y^{2}}{4}=1. Let S(p,q)S(p,q) be a point in the first quadrant such that p29+q24>1\dfrac{p^{2}}{9}+\dfrac{q^{2}}{4}>1. Two tangents are drawn from SS to the ellipse, of which one meets the ellipse at one end point of the minor axis and the other meets the ellipse at a point TT in the fourth quadrant. Let RR be the vertex of the ellipse with positive xx-coordinate and OO be the center of the ellipse. If the area of the triangle △ORT\triangle ORT is 32\dfrac{3}{2}, then which of the following options is correct?
  1. A.
    q=2, p=33q=2,\ p=3\sqrt{3}
  2. B.
    q=2, p=43q=2,\ p=4\sqrt{3}
  3. C.
    q=1, p=53q=1,\ p=5\sqrt{3}
  4. D.
    q=1, p=63q=1,\ p=6\sqrt{3}
Show answer

Correct option: A

[JEE Advanced 2024 · Paper 1]

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