JEE Advanced 2024 · Paper 1 · numerical answer

JEE Advanced 2024 Chemistry question on Coordination Compounds

Among V(CO)6\mathrm{V(CO)_6}, Cr(CO)5\mathrm{Cr(CO)_5}, Cu(CO)3\mathrm{Cu(CO)_3}, Mn(CO)5\mathrm{Mn(CO)_5}, Fe(CO)5\mathrm{Fe(CO)_5}, [Co(CO)3]3−\mathrm{[Co(CO)_3]^{3-}}, [Cr(CO)4]4−\mathrm{[Cr(CO)_4]^{4-}}, and Ir(CO)3\mathrm{Ir(CO)_3}, the total number of species isoelectronic with Ni(CO)4\mathrm{Ni(CO)_4} is ______. [Given, atomic number: V = 23, Cr = 24, Mn = 25, Fe = 26, Co = 27, Ni = 28, Cu = 29, Ir = 77]
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[JEE Advanced 2024 · Paper 1]

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