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JEE Advanced 2023 · Paper 1

JEE Advanced 2023 Physics question on Electromagnetic Induction and AC

A thin conducting rod MN of mass 20 gm, length 25 cm and resistance 10 Ω\Omega is held on frictionless, long, perfectly conducting vertical rails as shown in the figure. There is a uniform magnetic field B0=4B_0 = 4 T directed perpendicular to the plane of the rod-rail arrangement. The rod is released from rest at time t=0t = 0 and it moves down along the rails. Assume air drag is negligible. Match each quantity in List-I with an appropriate value from List-II, and choose the correct option.

[Given: The acceleration due to gravity g=10g = 10 m s−2^{-2} and e−1=0.4e^{-1} = 0.4]
  1. A.
    P→5,Q→2,R→3,S→1P \rightarrow 5, Q \rightarrow 2, R \rightarrow 3, S \rightarrow 1
  2. B.
    P→3,Q→1,R→4,S→5P \rightarrow 3, Q \rightarrow 1, R \rightarrow 4, S \rightarrow 5
  3. C.
    P→4,Q→3,R→1,S→2P \rightarrow 4, Q \rightarrow 3, R \rightarrow 1, S \rightarrow 2
  4. D.
    P→3,Q→4,R→2,S→5P \rightarrow 3, Q \rightarrow 4, R \rightarrow 2, S \rightarrow 5
Show answer

Correct option: D

[JEE Advanced 2023 · Paper 1]

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