JEE Advanced 2024 Physics question on Properties of Matter

A table tennis ball has radius $(3/2) \times 10^{-2}$ m and mass $(22/7) \times 10^{-3}$ kg. It is slowly pushed down into a swimming pool to a depth of $d = 0.7$ m below the water surface and then released from rest. It emerges from the water surface at speed $v$, without getting wet, and rises up to a height $H$. Which of the following option(s) is(are) correct?

[Given: $\pi = 22/7$, $g = 10$ m s$^{-2}$, density of water $= 1 \times 10^3$ kg m$^{-3}$, viscosity of water $= 1 \times 10^{-3}$ Pa·s.]