JEE Advanced 2024 · Paper 2

JEE Advanced 2024 Physics question on Gravitation

A particle of mass mm is under the influence of the gravitational field of a body of mass MM (≫m\gg m). The particle is moving in a circular orbit of radius r0r_0 with time period T0T_0 around the mass MM. Then, the particle is subjected to an additional central force, corresponding to the potential energy Vc(r)=mα/r3V_c(r) = m\alpha/r^3, where α\alpha is a positive constant of suitable dimensions and rr is the distance from the center of the orbit. If the particle moves in the same circular orbit of radius r0r_0 in the combined gravitational potential due to MM and Vc(r)V_c(r), but with a new time period T1T_1, then (T12−T02)/T12(T_1^2 - T_0^2)/T_1^2 is given by

[GG is the gravitational constant.]
  1. A.
    3αGMr02\dfrac{3\alpha}{GMr_0^2}
  2. B.
    α2GMr02\dfrac{\alpha}{2GMr_0^2}
  3. C.
    αGMr02\dfrac{\alpha}{GMr_0^2}
  4. D.
    2αGMr02\dfrac{2\alpha}{GMr_0^2}
Show answer

Correct option: A

[JEE Advanced 2024 · Paper 2]

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