JEE Advanced 2023 · Paper 2 · numerical answer

JEE Advanced 2023 Chemistry question on Solutions

50 mL of 0.2 molal urea solution (density = 1.012 g mL−1^{-1} at 300 K) is mixed with 250 mL of a solution containing 0.06 g of urea. Both the solutions were prepared in the same solvent. The osmotic pressure (in Torr) of the resulting solution at 300 K is ___.

[Use: Molar mass of urea = 60 g mol−1^{-1}; gas constant, R = 62 L Torr K−1^{-1} mol−1^{-1}; Assume, Δmix\Delta_{\text{mix}}H = 0, Δmix\Delta_{\text{mix}}V = 0]
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Answer: 682

[JEE Advanced 2023 · Paper 2]

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